I don't really understand how somebody stacks Xanax. Once you take it you can't retake another one for six hours, but before that the effects wear off. So how exactly can you stack it?
Question About Stacking
Started by Darcilyn_Andel [2107864] on in Questions & Answers.
About this thread
Posts archived: 8 / 8 posts (100%) · the total is Torn's reply count + the opening post at the last fetch
Counted by TornLife from the archived posts.
- Archived posts
- 8
- Discussion span
- →
- People posting
- 7
- Likes on archived posts
- 12
- Authority score
- 44 / 100
- Historical score
- 16 / 100
- Story score
- 32 / 100
- Engagement score
- 53 / 100
Most-liked replies
- AcidBadger [2231170]
· 6 likes ·
No, the effect doesn't wear off. You don't lose energy you have stacked. So you take one Xanax, and you have 250-400E. You keep that E until you take your next xanax and then you have 500-650E, and so on.
No, the effect doesn't wear off. You don't lose energy you have stacked. So you take one Xanax, and you have 250-400E. You keep that E until you take your next xanax and then you have 500-650E, and so on.
Stacking is usually referring to taking xan until you reach the maximum of 1,000 energy, which takes about 2 days. Typically used for happy jumps or big chains.
Additionally, if you want to hit the max 1000 exactly so you can earn the merit, drain your energy to zero before taking that first Xanax. It may seem like obvious, simple math, but some of us don’t think about it right away.
of course you can always use energy while you are on Xanax to get to the right number too...
of course you can always use energy while you are on Xanax to get to the right number too...
As said above it is great for use in chaining or happy jump training. You can't use refills or gain natural E from regen while stacking, so only do it for those purposes ;)
Thanks. I was spending the energy as soon as I took the Xanax.
keep in mind that 1k energy is the cap, you cannot go above that by taking another Xanax (it'll count as a waste).
And revive $$, lol