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High Low

Started by Wires [2209713] on in General Discussion.

46 replies · 1.11k views · thread synced · 3 days ago · View on torn.com
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Wires [2209713]
Okay. Let me preface this by saying I'm not a gambler. I don't like it very much, and that leads to inexperience.

So I have a go with 10 Torn Pixels to try and get merits like High and Low. And I have to ask - does anyone know the actual odds of successfully pulling 25 in a row?

Providing you always pick the highest odds, something I might miss occasionally, can it be boiled down to a % chance?

Because I've lost next to no money on it but STILL want to brain myself over it.

'Oh. Okay. Of course it's the 4th ace in the deck now that I've pulled a king.'

-.-
flare [2195157] Officer Officer
This is what chat gpt said using this prompt:

What are the odd's of getting 25 wins in a row in a game of high low considering the deck will randomly shuffle

[image: sxcu.net]

It likes to lie sometimes though, or make stuff up so take it with a grain of salt
flare [2195157] Officer Officer
Deck shuffles randomly in high low iirc. I tried including that in the prompt but it doesn't seem like it added it in the calculations lol
Insi [2034939]
Providing you always pick the highest odds

If you always pick the highest odds you'll never get it

Math probably doesn't back up my assertion but I'll stand by it anyway
Shlefter [2901183]
tl;dr ~0.1417% or 705 attempts

Assuming a tie does not penalise the streak:
Then if the first card is a X then you have a Y chance of guessing correctly:
xy
212/12
311/12
410/12
59/12
68/12
77/12
86/12
97/12
108/12
J9/12
Q10/12
K11/12
A12/12
Since the chance of drawing x is a uniform distribution, your probability of winning a given game is the mean if the y vector (120/156 ~ 0.769). A random single draw would follow a Bernoulli(p=120/156) distribution. Therefore a game with 25 rounds would follow Binomial(n=25, p=120/156), and your chance of winning all 25 is as you say, p25. Which would be (120/156)25 ~ 0.00141715. The number of games you'd have to play to win 25 rounds in a row would follow Geometric(p~0.00141715) and as you say, you'd expect around 1/p games before you win 25 rounds.

This gives approximately 705.6 games to get the merit.

Stolen from reddit, math checks out. It might be a little bit off because of counting cards but idk how that would affect the odds. The chatGPT answer is wrong because it claims a 50% chance of winning each round while the reality is much higher.

There's a torntools setting that makes this pretty mindless and not too difficult to get.
RonBurgundy [71545]
It's conditional.

If you have a streak of 5, you are allowed to progress naturally.

If you have a streak of 10, you will be shuffled on more often.

If you have a streak of 15, you will receive deterministic losses.

If you have a streak of 20, there is a 10 coin flip and if any given 1 is a loss, you lose.

If you are on 24, it checks your stats and if you have under 1,000 completed games it gives you a losing card.

It's honestly not that complicated.
Awesome-O [2356036]
It can be done... I did it

It took ages

Staff Edit: This is not allowed as per the scripting guidelines

But I got it eventually
Beerstein [1322136]
Average in Torn seems to be 1-2 weeks between everyone I talked to about it so anecdotally that checks out. It's certainly not as bad as many think.
Sepulchrave [2092631]
Apparently ChatGPT is a retard.

Schlefter got it right. There are no fixed odds for hi/low because the odds change every turn.

If your base card is an ace or a king the odds are 100% that you will win (if you're a rational agent).

If your base card is a seven or eight the odds of success are much lower.
Fermion [2691036] Officer Officer
Autoclickers would be against scripting rules, so don't use that. Hi low helper in torn tools is great and helped me get it. Took a lot of tokens, but it was just mindlessly clicking for 25 times. It even removes the unlikely option button